Pixel Crushers Forum

Posted: **Wed Nov 18, 2020 1:44 pm**

We tried to make script in dialogue a bit more complex (and we don't have any lua experience) and got this error:

Dialogue System: Lua code 'if Variable["TrainStartSequence"] == 0 then Variable["TrainStartSequence"] = 1' threw exception 'Code has syntax errors:
Line 2, Col 1 : Failed to parse Letter of Name.
Line 2, Col 1 : Failed to parse Name of VarName.

Is it possible to use if/then statement in script field? And if it is possible, how to do it properly?

Posted: **Wed Nov 18, 2020 2:12 pm**

Hi,

Lua is mostly like C#, but 'if' statements are a little different because that have to end with the 'end' keyword. Try this:

Code: Select all

if Variable["TrainStartSequence"] == 0 then Variable["TrainStartSequence"] = 1 end

Or, for better readability:

Code: Select all

if (Variable["TrainStartSequence"] == 0) then 
     Variable["TrainStartSequence"] = 1 
 end

Alternatively, you could use math.max() to guarantee that the variable is at least 1:

Code: Select all

Variable["TrainStartSequence"] = math.max(1, Variable["TrainStartSequence"])

Posted: **Thu Nov 19, 2020 9:14 am**

Thanks for the quick response!

Posted: **Thu Nov 19, 2020 10:04 am**

Glad to help!

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